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add support for declaring css output in esbuild call

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This commit is contained in:
Damien Elmes 2021-03-21 15:42:14 +10:00
parent 860ae5464c
commit 1e14384d88
1 changed files with 10 additions and 1 deletions
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11
ts/esbuild/upstream.bzl
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@ -89,6 +89,8 @@ def _esbuild_impl(ctx):
js_out = ctx.outputs.output
js_out_map = ctx.outputs.output_map
outputs.extend([js_out, js_out_map])
if ctx.outputs.output_css:
outputs.append(ctx.outputs.output_css)
if ctx.attr.format:
args.add_joined(["--format", ctx.attr.format], join_with = "=")
@ -187,6 +189,10 @@ See https://esbuild.github.io/api/#splitting for more details
mandatory = False,
doc = "Name of the output source map when bundling",
),
"output_css": attr.output(
mandatory = False,
doc = "Name of the output css file when bundling",
),
"platform": attr.string(
default = "browser",
values = ["node", "browser", "neutral", ""],
@ -228,12 +234,14 @@ For further information about esbuild, see https://esbuild.github.io/
""",
)
def esbuild_macro(name, output_dir = False, **kwargs):
def esbuild_macro(name, output_dir = False, output_css = False, **kwargs):
"""esbuild helper macro around the `esbuild_bundle` rule
For a full list of attributes, see the `esbuild_bundle` rule
Args:
name: The name used for this rule and output files
output_dir: If `True`, produce a code split bundle in an output directory
output_css: If `True`, declare a .css file will be outputted, which is the
case when your code imports a css file.
**kwargs: All other args from `esbuild_bundle`
"""
@ -248,5 +256,6 @@ def esbuild_macro(name, output_dir = False, **kwargs):
name = name,
output = "%s.js" % name,
output_map = "%s.js.map" % name,
output_css = None if not output_css else "%s.css" % name,
**kwargs
)