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only look at the last 10 answers for time

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Damien Elmes 2011-04-24 13:32:30 +09:00
parent 0bbdd722c2
commit 3327c27d81
1 changed files with 4 additions and 3 deletions
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7
anki/sched.py
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@ -105,13 +105,14 @@ order by due""" % self._groupLimit(),
"A very rough estimate of time to review."
(cnt, sum) = self.deck.db.first("""
select count(), sum(taken) from (select * from revlog
order by time desc limit 100)""")
order by time desc limit 10)""")
if not cnt:
return 0
avg = sum / float(cnt)
c = self.counts()
# Here we just assume new/lrn will require 3x the number of reviews. A
# more complex solution can be added in the future.
# Here we just assume new/lrn will require 3x the number of reviews.
# To improve on this we'll need to make grade count down so we can get
# a decent picture of required steps.
return (avg*c[0]*3 + avg*c[1]*3 + avg*c[2]) / 1000.0
# Counts