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allow the user to choose if case should be folded

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This commit is contained in:
Damien Elmes 2011-04-14 03:49:25 +09:00
parent bee14e1a0b
commit 8b747c3aac
2 changed files with 6 additions and 4 deletions
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4
anki/deck.py
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@ -643,8 +643,8 @@ update facts set tags = :t, mod = :n where id = :id""", [fix(row) for row in res
def findCards(self, query):
return anki.find.Finder(self).findCards(query)
def findReplace(self, fids, src, dst, regex=None, field=None):
return anki.find.findReplace(self, fids, src, dst, regex, field)
def findReplace(self, fids, src, dst, regex=None, field=None, fold=True):
return anki.find.findReplace(self, fids, src, dst, regex, field, fold)
def findDuplicates(self, fmids):
return anki.find.findDuplicates(self, fmids)

6
anki/find.py
View file

@ -353,7 +353,7 @@ where mid in %s and flds like ? escape '\\'""" % (
# Find and replace
##########################################################################
def findReplace(deck, fids, src, dst, regex=False, field=None):
def findReplace(deck, fids, src, dst, regex=False, field=None, fold=True):
"Find and replace fields in a fact."
mmap = {}
if field:
@ -366,7 +366,9 @@ def findReplace(deck, fids, src, dst, regex=False, field=None):
# find and gather replacements
if not regex:
src = re.escape(src)
regex = re.compile("(?i)"+src)
if fold:
src = "(?i)"+src
regex = re.compile(src)
def repl(str):
return re.sub(regex, dst, str)
d = []