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When a user has learning steps that extend past the daily cutoff, we end up counting them all instead of only the ones that would be done today. In order to avoid this without expensive calculations or db schema changes, we calculate the number of steps until the daily cutoff and pack it into the left column, as totalLeft + leftToday*1000.
88 lines
2.2 KiB
Python
88 lines
2.2 KiB
Python
# coding: utf-8
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import time
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from tests.shared import assertException, getEmptyDeck
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from anki.consts import *
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def test_op():
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d = getEmptyDeck()
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# should have no undo by default
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assert not d.undoName()
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# let's adjust a study option
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d.save("studyopts")
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d.conf['abc'] = 5
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# it should be listed as undoable
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assert d.undoName() == "studyopts"
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# with about 5 minutes until it's clobbered
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assert time.time() - d._lastSave < 1
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# undoing should restore the old value
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d.undo()
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assert not d.undoName()
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assert 'abc' not in d.conf
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# an (auto)save will clear the undo
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d.save("foo")
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assert d.undoName() == "foo"
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d.save()
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assert not d.undoName()
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# and a review will, too
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d.save("add")
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f = d.newNote()
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f['Front'] = u"one"
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d.addNote(f)
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d.reset()
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assert d.undoName() == "add"
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c = d.sched.getCard()
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d.sched.answerCard(c, 2)
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assert d.undoName() == "Review"
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def test_review():
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d = getEmptyDeck()
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d.conf['counts'] = COUNT_REMAINING
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f = d.newNote()
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f['Front'] = u"one"
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d.addNote(f)
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d.reset()
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assert not d.undoName()
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# answer
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assert d.sched.counts() == (1, 0, 0)
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c = d.sched.getCard()
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assert c.queue == 0
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d.sched.answerCard(c, 2)
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assert c.left == 1001
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assert d.sched.counts() == (0, 1, 0)
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assert c.queue == 1
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# undo
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assert d.undoName()
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d.undo()
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d.reset()
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assert d.sched.counts() == (1, 0, 0)
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c.load()
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assert c.queue == 0
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assert c.left != 1001
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assert not d.undoName()
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# we should be able to undo multiple answers too
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f['Front'] = u"two"
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d.addNote(f)
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d.reset()
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assert d.sched.counts() == (2, 0, 0)
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c = d.sched.getCard()
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d.sched.answerCard(c, 2)
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c = d.sched.getCard()
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d.sched.answerCard(c, 2)
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assert d.sched.counts() == (0, 2, 0)
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d.undo()
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d.reset()
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assert d.sched.counts() == (1, 1, 0)
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d.undo()
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d.reset()
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assert d.sched.counts() == (2, 0, 0)
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# performing a normal op will clear the review queue
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c = d.sched.getCard()
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d.sched.answerCard(c, 2)
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assert d.undoName() == "Review"
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d.save("foo")
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assert d.undoName() == "foo"
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d.undo()
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assert not d.undoName()
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